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32m^2-72m+16=0
a = 32; b = -72; c = +16;
Δ = b2-4ac
Δ = -722-4·32·16
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-56}{2*32}=\frac{16}{64} =1/4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+56}{2*32}=\frac{128}{64} =2 $
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